Question

Using herons formula find the area of a field which is in the shape of rhombus with side measureing 100m and it's diagonal is 160m

Answer 1

Answer:

let ABCD is the field

perimeter = 400m

so each side = 400 ÷4 =100 m

AB = AD = 100m

let diagonal BD = 160 m

then semi perimeter s of ∆ABD is given by

s = 100 +100 + 160 ÷ 2 = 180 m

therefore area of ∆ ABD

= √180 ( 180 - 100 ) (180 -100 ) ( 180 - 160 )

= √ 180 × 80 × 80 × 20 m ^2

= 4800 m ^ 2