using herons formula find the area of an equilateral triangle whose perimeter is 24cm
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we know that the sides of an equilateral Triangle are equal.
given he perimeter of the equilateral Triangle = 24cm
therefore side × 3 = 24cm
==> side = 24/3
==> side = 8cm
hence, all sides of the equilateral Triangle is 8cm.
let the sides of the triangle be a, b and c.
according to heron's formula, we have to first find it's semi-perimeter.
semi-perimeter of the triangle = 24/2 = 12cm
area of the triangle by heron's formula = √s(s-a)(s-b)(s-c)
= √12(12-8)(12-8)(12-8)
= √12×4×4×4
= √768
= (2 × 2 × 2)√6
= 16√3 cm²
the area of the equilateral Triangle is 16√3 cm²
HOPE THIS HELPS..!!
given he perimeter of the equilateral Triangle = 24cm
therefore side × 3 = 24cm
==> side = 24/3
==> side = 8cm
hence, all sides of the equilateral Triangle is 8cm.
let the sides of the triangle be a, b and c.
according to heron's formula, we have to first find it's semi-perimeter.
semi-perimeter of the triangle = 24/2 = 12cm
area of the triangle by heron's formula = √s(s-a)(s-b)(s-c)
= √12(12-8)(12-8)(12-8)
= √12×4×4×4
= √768
= (2 × 2 × 2)√6
= 16√3 cm²
the area of the equilateral Triangle is 16√3 cm²
HOPE THIS HELPS..!!
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