Question

using herons formula find the sides 20,20,24​

Answer 1

Answer:

s= a+b+c/2

so s=64/2=32

area of heron formula= √s(s-a)(s-b)(s-c)

=√32(32-20)(32-20)(32-24)

=√32×12×12×18

=4×2×3×3×2√2

144√2

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Answer 2

ANSWER✔

$\large\underline\bold{GIVEN,}$

$\sf\therefore side\:of\:triangle,$

$\sf\dashrightarrow a=20$

$\sf\dashrightarrow b=20$

$\sf\dashrightarrow c=24$

$\large\underline\bold{TO\:FIND,}$

$\sf\dashrightarrow\text{area of triangle (by using herons formula.}$

✯.FOMULA IN USE,

$\large{\boxed{\bf{ \star\:\:AREA\:OF\: TRIANGLE= \sqrt{ s(s-a)(s-b)(s-c)} \:\: \star}}}$

$\large\underline\bold{SOLUTION,}$

$\sf\therefore \text{ here,we don't know the value of 's'.}$

$\sf\therefore we\:know,$

$\bf{\:\:\:\:\:\:\:\:\:\:\:\dashrightarrow s=\dfrac{ a+b+c}{2} }$

$\sf\implies s= \dfrac{20+20+24}{2}$

$\sf\implies s= \dfrac{64}{2}$

$\sf\implies s=\cancel \dfrac{64}{2}$

$\sf\implies s= 32$

$\large{\boxed{\bf{ \star\:\: s=32\:\: \star}}}$

$\sf\large\therefore\text{ Now, putting all the values in the formula.we get,}$

$\sf\dashrightarrow \sqrt{32(32-20)(32-20)(32-24)}$

$\sf\implies \sqrt{32(12)(12)(8)}$

$\sf\implies 12 \sqrt{ 32 \times 8}$

$\sf\implies 12 \sqrt{256}$

$\sf\implies 12 \times 16$

$\sf\implies 192sq.units$

$\large{\boxed{\bf{ \star\:\: AREA\:OF\:TRIANGLE=192\:sq.units\:\: \star}}}$

$\large\underline\bold{AREA\:OF\:TRIANGLE\:IS\:192\:sq.units}$

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