Question

using hugens principal deduce the laws of reflection​

Answer 1

Explanation:

The laws of reflections are verified using Huygens's Principle. The incident ray, the reflected ray and normal to the reflecting surface lie in one plane which is perpendicular to the reflecting surface. The angle of incidence equals angle of reflection.

Answer 2

Answer:

$\huge\underline\mathfrak\pink{Answer}$

from the As ACD and MCL, we have

AD/ML=AC/MN............(1)

similarly, in triangle ACE and MCN

AE/MN=AC/MN..........(2)

from(1) and (2), we have

AD/ML=AE/MN

=>AE/AD=BC/AD=C1t/C2t=MN/ML

BC/AD=MN/ML=C1/C2

hence, AD is the radius for secondary wavefront from the point A, then Ml. let I and r be the angle of incidence and refraction respectively. from the triangles ABC and ACD.

suni/sine=BC/AC÷AD/AC=BC/AD=C1t/C2t=C1/C2=MUE1/MUE2

where MUE2 is the refractive index of second medium with respect to first medium the above relation is snell's law.

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I hope this helps you........