Using huygen's principle, verify the lawson reflection at a plane surface.
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Answer:
Consider any point Q on the incident wavefront PA. When the disturbance from P on incident wavefront reaches point P', the disturbance from point Q reaches Q' If c is the velocity of light, then the time taken by light to go from point Q to Q' (via point K) is given by, In right-angled ΔAQK, ∠QAK = i ∴ QK = AK sin i In right-angled ΔKQ'P' ∠Q'P'K = r ∴ KQ′ = KP′sinr Substituting these values in equation (1), The rays from different points on incident wavefront will take the same time to reach the corresponding points on the reflected wavefront if ‘t’ given by equation (ii) is independent of AK ∴ AK (sin i − sin r) = 0 sin i − sin r = 0 sin i = sin r i = r i.e the angle of incidence is equal to the angle of reflection Also, the incident ray (LA or MP'), reflected ray (AA'L' or P'M'), and the normal (AN) − all lie in the same.