Question

using identies evalute :(99)power 2​

Answer 1

$\large \sf\underline{ \underline{ \red{solution : }}} \:$

$\implies \tt{ {99}^{2} } \\ \\ \\ \implies\tt{(100 - {1)}^{2} } \\ \\ \\ \boxed{\sf{ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} }}$

Here ,

• x = 100

• y = 1

$\\ \\ \implies \tt{ {100}^{2} - 2(100)(1) + {1}^{2} } \\ \\ \\ \implies{ \tt{10000 - 200 + 1} } \\ \\ \\ \implies \tt{10000 - 199} \\ \\ \\ \implies \boxed{ \tt{ { {99}^{2} = \blue{ 9801}}}}$

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Other identities :-

• ( x + y )² = x² + 2xy + y²

• x² - y² = ( x + y ) ( x - y )

• ( x + y )³ = x³ + 3x²y + 3xy² + y³

• ( x - y )³ = x³ - 3x²y + 3xy² + y³