Question

using identies finds
1. 199³
2. (10+11)³​

Answer 1

Answer:

1. 7880599

2. 9261

Step-by-step explanation:

1. 199 can be written as 100 +99 so., (100 + 99)^3 ..we should apply (a+b)^3 formula that is a^3 + b^3 +3ab(a+b)

by applying this formula we get 100^3 +99^3 + 3×100×99(100+99)

by solving above identity we get 1000000 + 970288 + 5910300 = 7880599

we can verify by multiplying 199 ×199×199 = 7880599 ...so we get the correct answer

2. (10+11)^3 we should apply the (a+b)^3 formula that is

(a+b)^3 =a^3 + b^3 +3ab(a+b)

so we have to substitute a=10 and b = 11

10^3 + 11^3 + 3×10×11 (10+11)

=1000+1331 + 330(21)

by solving above we get 9261