Question

Using Identitie (x+y)^3=x^3+y^3+3xy(x+y)
Solve (100+2)^3

Answer 1

Hello Mate!

As we know that

( x + y ) ^ 3 = x^3 + y^3 + 3xy ( x + y )

( 100 + 2 )^3 = 100^3 + 2^3 + 3(100)(2) ( 100 + 2 )
= 1000000 + 8 + 600 × 102
= 1000008 + 61200
= 1061208

Hope it helps☺!✌

Answer 2

Hey!

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Solution :-

Question = (100 + 2)³

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•Solution :-

Identity :-

(x + y)³ = x³ + y³ + 3xy(x + y)

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= (100)³ + (2)³ + 3 × 100 × 2 (100 + 2)

= 1000000 + 8 + 600 × 102

= 1000008 + 61200

= 1061208


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Regards :)

Cybary

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