using identities , evaluate 1.05 ×
9.5
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1.05×9.5
1.05 × 0.95 × 10
(1 + 0.05)× (1− 0.05) × 10
[(1)² − (0.05)²] × 10
[1 − 0.0025] × 10
0.9975 × 10
9.975Ans
1.05 × 0.95 × 10
(1 + 0.05)× (1− 0.05) × 10
[(1)² − (0.05)²] × 10
[1 − 0.0025] × 10
0.9975 × 10
9.975Ans
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