Question

Using identities, evaluate:2.02 sq-0.98 sq
$2.02 {}^{2} - 0.98 {}^{2}$

Answer 1

Ans: a^2 - b^2 = ( a+b)(a-b)

= (2.02)^2 - (0.98)^2
= ( 0.02 + 0.98) (0.02 - 0.98)
= (1) (- 0.96)
= −0.96

Hope it helps...!!