using identities , evaluate 78multiple 82
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Answered by
1
Hey mate!
Here is your answer > >
78×82 can be written as (80-2)*(80+2)
We know that
(a-b)(a+b)=a^2-b^2
In this question, a is 80 and b is 2
So, 80^2-2^2=6400-4=6396
Hope it helps!
Thankyou ☆ ☆
Bebrainly
Here is your answer > >
78×82 can be written as (80-2)*(80+2)
We know that
(a-b)(a+b)=a^2-b^2
In this question, a is 80 and b is 2
So, 80^2-2^2=6400-4=6396
Hope it helps!
Thankyou ☆ ☆
Bebrainly
Answered by
3
78 × 82
=> (80-2)(80+2)
using identity
(a-b)(a+b) = a² - b²
=> (80)² - (2)²
=> 6400 - 4
=> 6396 .... answer
.......................
Hope it may help you.
=> (80-2)(80+2)
using identity
(a-b)(a+b) = a² - b²
=> (80)² - (2)²
=> 6400 - 4
=> 6396 .... answer
.......................
Hope it may help you.
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