Math, asked by simrankhatana2227, 1 year ago

using identities evaluate 99x101

Answers

Answered by Siddhant02
3
(100-1)(100+1)
using identity : (a+b)(a-b)= (a^2-b^2)
then
(100)^2-(1)^2
=10000-1= 9999
This is the answer of your question:-))
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