using identities evaluate 99x101
Answers
Answered by
3
(100-1)(100+1)
using identity : (a+b)(a-b)= (a^2-b^2)
then
(100)^2-(1)^2
=10000-1= 9999
This is the answer of your question:-))
using identity : (a+b)(a-b)= (a^2-b^2)
then
(100)^2-(1)^2
=10000-1= 9999
This is the answer of your question:-))
Similar questions
Social Sciences,
7 months ago
Science,
7 months ago
Science,
1 year ago
Science,
1 year ago
Computer Science,
1 year ago