Question

Using identities, evaluate.
(i)712
(ii) 9982​

Answer 1

Step-by-step explanation:

(I) 712= (700+12)²

(a+b)² = a² +2ab + b²

= 700² + 2 x 700 x 12 + (12)²

= 506944

Answer 2

Answer:(1) 712

Given, 712.

It can be written as (70+1)2.

Use identity (a+b)2=a2+2ab+b2.

Simplifying the expression we get,

(70+1)2=(70)2+2×70×1+(1)2=4900+140+1=5041

Therefore, value of 712 is 5041.

(2) 9982

Given, 9982.

It can be written as (1000−2)2.

Use identity (a−b)2=a2−2ab+b2.

Simplifying the expression we get,

(1000−2)2=(1000)2−2×1000×2+(2)2=1000000−4000+4=996004

Therefore, value of 9982 is 996004.

Step-by-step explanation:

This Answer is 100% True Answer