Question

Using identities evaluate
$27 {x}^{3} - 63 {x}^{2} + 49x - \frac{343}{27}$
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Answer 1

Answer:

[3x-7^3]^3

Step-by-step explanation:

(a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3

Compare 27x^3 - 63x^2 + 49x - 343/27 to a^3 - 3a^2b + 3ab^2 - b^3

We can deduce that 27x^3 = a^3 or (3x)^3 = a^3

∴ a = 3x

And 343/27 = b^3 or [7^3]×3 = b^3

∴ b = 7^3

So, 27x^3 - 63x^2 + 49x - 343/27

= [3x−7^3]^3

Answer 2

Answer:

I am really sorry Army I don't know the answer of this question