Math, asked by ShabhariRaamKishoreK, 3 months ago

.Using identities, evaluate
(i) \:  {99}^{2}  \:  \: (ii) {102}^{2}

please answer fast.its emergency.​

Answers

Answered by Anonymous
2

Answer:

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Answered by princess1224
2

Answer:

 {99}^{2}  \\  {(100 - 1)}^{2}  \\  {a}^{2}  - 2ab +  {b}^{2}  \\  {100}^{2} - 2 \times 100 \times 1 +  {1}^{2}   \\ 10000 - 200 + 1 \\ 10001 - 200 \\ 9801

 {101}^{2}  \\  {(100 + 1)}^{2} \\  {a}^{2}   + 2ab +  {b}^{2}  \\  {100}^{2}  + 2 \times 100  \times 1 +  {1}^{2}  \\ 10000 + 200 + 1 \\ 10201

hope it helps you dear....

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