Question

using identities , evaluate the following
${99}^{2}$
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Answer 1

Answer:

heya mate ...

(99)² = a²+b²+2ab

(100+1)² = 100² +1²+2×100×1

10000+1+ 200

102001

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Answer 2

AnswEr :

There is A Very Commonly Used Mathematical Identity, Which Follows :

• ( a + b )² = a² + b² + 2ab

• ( a – b )² = a² + b² - 2ab

We are Going to Use (a - b)² identity here.

⇒ ( 99 )²

⇒ ( 100 - 1 )²

• we can write 99 as [ 100 - 1 = 99 ]

⇒ (100)² + (1)² - (2 × 100 × 1)

⇒ 10,000 + 1 - 200

⇒ 10,001 - 200

⇒ 9,801

჻ we get (99)² = 9801 using identity (a - b)²