Question

Using identities factorise
(m+n)²-4mn​

Answer 1

Step-by-step explanation:

Given:-

(m+n)^2-4mn

To find:-

Using identities factorise (m+n)^2-4mn

Solution:-

Method-1:-

Given expression is (m+n)^2-4mn

We know that (a+b)^2 = a^2+2ab+b^2

=> (m^2+2mn+n^2)-4mn

=> m^2+2mn+n^2-4mn

=>m^2-2mn+n^2

=>m^2-2(m)(n)+n^2

This is in the form of a^2-2ab+b^2

Where a = m and b=n

=>a^2-2ab+b^2 = (a-b)^2

=> (m-n)^2

=> (m-n)(m-n)

Method -2:-

Given expression is (m+n)^2-4mn

This is in the form of (a+b)^2-4ab

Where a = m and b = n

We know that

(a+b)^2-4ab = (a-b)^2

=>(m+n)^2-4mn

=> (m-n)^2

=> (m-n)(m-n)

Answer:-

The factorization of (m+n)^2-4mn is (m-n)(m-n)

Used Identities :-

• (a+b)^2 = a^2+2ab+b^2

• (a-b)^2=a^2-2ab+b^2

• (a+b)^2-4ab = (a-b)^2

Answer 2

Answer

m^2 + 2mn + n^2 -4mn

m^2 - 2mn + n^2

m^2 - mn - mn + n^2

m(m-n) - n(m-n)

(m-n)( m-n). Answer...