Question

Using identities factorise the following-: (x-2y)²+8xy​

Answer 1

Step-by-step explanation:

(x-2y)^2+8xy=x^2+4y^2-4xy+8xy

=x^2+4y^2+4xy

Answer 2

Given

can be written as

$\longmapsto\tt{(x-2y)^2 + 8xy }$

We know that

$\longmapsto\tt{(a-b)^2 = a^2 + b^2 - 2ab.}$

$\longmapsto\tt{x^2 + 2y^2 - 4xy + 8xy}$

$\longmapsto\tt{x^2 + 2y^2 + 4xy}$

$\longmapsto\tt{(x + 2y)^2.}$