Question

Using identities find the value of 42^2-38^2

Answer 1

Answer:

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Answer 2

${42}^{2} - {38}^{2}$

${x}^{2} - {y}^{2} = (x - y)(x + y)$

$= (42 - 38)(48 + 38)$

$= (4) \times (80)$

$= 320$

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