Using identities, find the value of
i) 99 square ii) 78x82
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Answer:
i) 99 square
= (100-1)^2
= [(100)^2 + (1)^2 -2×100×1]
= 10000 + 1 -200
= 9801 (a - b)^2
ii) 78 × 82
= (100 - 22) ( 100 -18)
= (100)^2 + (-22-18)100 + (-22) (-18)
= 10000 - 4000 + 396
= 6000+396
= 6396 ( x + a) (x + b)
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