Question

using identities x-y=6; xy=4, find the value of x3-y3?

Answer 1

Given x - y = 6 and xy = 4

          (x - y)^2 = 36

          x^2 + y^2 - 2xy = 36

          x^2 + y^2 - 8 = 36

          x^2 + y^2 = 44   ---- (1)


x^3 - y^3 = (x-y)(x^2+y^2+xy)

               = 6(44 + 4)

               = 6(48)

                = 288.

Answer 2

Answer:

288

Step-by-step explanation:

Given:

x-y=6

xy=4

To prove:

$x^{3} -y^{3}$

Solution:

Fundamentally, it is a parity that is accepted as accurate for each value of the variables. Only a small set of numbers, though, are considered valid for an equation. An equation is not an identity just because of this particular feature.

A polynomial with two variables is called a binomial. It describes the powers' algebraic expansion. Combinatorics, algebra, calculus, and many other branches of mathematics can all benefit from the theorem and its generalisations for proving conclusions and resolving issues.

$(x-y)^{3} =x^{3} -y^{3}-3 x^{2}y+3x y^{2}$

Substituting the value in the equation,

$6^{3} =x^{3} -y^{3} -3x^{2} y+3xy^{2} \\216=x^{3} -y^{3} -3yx(x-y)\\216=x^{3} -y^{3}-(3)(4)(6)\\216=x^{3} -y^{3}-72\\216+72=x^{3} -y^{3}\\288=x^{3} -y^{3}$

To verify algebraic identity a2-b2=(a+b)(a-b)

https://brainly.in/question/10726280

Find value using appropriate algebraic identities.

152²-148²

give me answer​

https://brainly.in/question/49239186

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