Math, asked by anjali181986, 7 months ago

using identity 1. (99)² 2. (106)³ give me solution​

Answers

Answered by monikamodi1982
0

1) (99)^2

(100-1)^2

100^2 -2(100)(1) + 1^2

10000 - 200 + 1

9801

99^2 = 9801

2) (106)^3

(100+6)^3

100^3 + 6^3 + 3(100)(6)(100+6)

1000000+216+180000+10800

1191016

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