Math, asked by ashokgevaria, 1 month ago

Using identity (a+b)^2 = a^2 + 2ab +b^2 find the value of 103^2
pls tell the answer of this ​

Answers

Answered by NamanSheoran
0

Answer:

(100+3)^2

Using identity (a+b) ^2 =a^2 +b^2 +2ab

(100)^2 +(3)^2 +2×100×3

10000+9+600

=10609 is ans

Step-by-step explanation:

(100+3)^2

Using identity (a+b) ^2 =a^2 +b^2 +2ab

(100)^2 +(3)^2 +2×100×3

10000+9+600

=10609 is ans

Answered by psoren650
0

Answer:

(103)²=(100+3)²

=100²+2.100.3+3²

=10000+600+9

=10609

Step-by-step explanation:

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