using identity, evaluate 104into 96
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104×96
(100+4)(100-4)=>100²-4²
10000-16=>9984
(100+4)(100-4)=>100²-4²
10000-16=>9984
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![104 \times 96 \\ \\ we \: can \: write \: it \: as \\ \\ (100 + 4) \times (100 - 4) \\ \\ = (100 + 4)(100 - 4) \\ \\ using \: the \: identity \\ \\ (a + b)(a - b) = {a}^{2} - {b}^{2} \\ \\ (100 + 4)(100 - 4) \\ \\ = {(100)}^{2} - {(4)}^{2} \\ \\ = 10000 - 16 \\ \\ = 9984 104 \times 96 \\ \\ we \: can \: write \: it \: as \\ \\ (100 + 4) \times (100 - 4) \\ \\ = (100 + 4)(100 - 4) \\ \\ using \: the \: identity \\ \\ (a + b)(a - b) = {a}^{2} - {b}^{2} \\ \\ (100 + 4)(100 - 4) \\ \\ = {(100)}^{2} - {(4)}^{2} \\ \\ = 10000 - 16 \\ \\ = 9984](https://tex.z-dn.net/?f=104+%5Ctimes+96+%5C%5C++%5C%5C+we+%5C%3A+can+%5C%3A+write+%5C%3A+it+%5C%3A+as+%5C%5C++%5C%5C+%28100+%2B+4%29+%5Ctimes+%28100+-+4%29+%5C%5C++%5C%5C++%3D+%28100+%2B+4%29%28100+-+4%29+%5C%5C++%5C%5C++using+%5C%3A+the+%5C%3A+identity+%5C%5C++%5C%5C+%28a+%2B+b%29%28a+-+b%29++%3D++%7Ba%7D%5E%7B2%7D++-++%7Bb%7D%5E%7B2%7D++%5C%5C++%5C%5C+%28100+%2B+4%29%28100+-+4%29+%5C%5C++%5C%5C++%3D++%7B%28100%29%7D%5E%7B2%7D++-++%7B%284%29%7D%5E%7B2%7D++%5C%5C++%5C%5C++%3D+10000+-+16+%5C%5C++%5C%5C++%3D+9984)
Hope this helps!!!
@Mahak24
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Here is the answer you were looking for:
Hope this helps!!!
@Mahak24
Thanks...
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