using identity , evaluate :
(i) 1.05 × 0.95
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1÷100{(10+0.05)(10-0.05)
a^2×b^2=(a+b)(a-b)
a=10 , b=0.05
1÷100{a^2×b^2}
1÷100{10^2×0.05^2}
1÷100{100×0.25}
1÷100×99.75
99.75÷100
0.9975
a^2×b^2=(a+b)(a-b)
a=10 , b=0.05
1÷100{a^2×b^2}
1÷100{10^2×0.05^2}
1÷100{100×0.25}
1÷100×99.75
99.75÷100
0.9975
sanwi17062006:
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Answered by
0
0.9975 is the answer
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