using identity expand
(2a-3b-4c)^2
Answers
Answered by
2
Answer:
2a + 3b + 4c)^2 = (2a)^2 + (3b)^2 + (4c)^2 + 2(2a)(3b) + 2(3b)(4c) + 2(4c)(2a). = 4a^2 + 9b^2 + 16c^2 + 12ab + 24bc + 16ca.
Similar questions