Math, asked by sarkarmanjita317, 3 months ago

using identity expand
(2a-3b-4c)^2

Answers

Answered by ltzSweetAngel
2

Answer:

2a + 3b + 4c)^2 = (2a)^2 + (3b)^2 + (4c)^2 + 2(2a)(3b) + 2(3b)(4c) + 2(4c)(2a). = 4a^2 + 9b^2 + 16c^2 + 12ab + 24bc + 16ca.

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