Math, asked by adnankhan4981, 5 months ago

Using identity expand (3a+4b)3​

Answers

Answered by akshasen15
1

(3a+4b)^3

= (3a+4b)(3a+4b)(3a+4b)

= (3a)^3+(4b)^3+3 (3a)(4b)(3a+4b)

= 27a3 + 64b3 +36ab(3a+4b)

= 27a3 + 64b3 +(108a2 b+144a b2)

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