Using identity find (103)the whole cube
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• (103)^3 = ?
= (103)^3 = (100+3)^3
As we know that, (a+b)^3 = a^3 + b^3 + 3ab(a+b) .
here, a = 100 & b = 3 .
So,
= (100+3)^3 = 100^3 + 3^3 + 3(100)(3)(100+3)
= (103)^3 = 1000000 + 27 + 900(103)
= (103)^3 = 1000000 + 27 + 92700
= (103)^3 = 1092727
= (103)^3 = (100+3)^3
As we know that, (a+b)^3 = a^3 + b^3 + 3ab(a+b) .
here, a = 100 & b = 3 .
So,
= (100+3)^3 = 100^3 + 3^3 + 3(100)(3)(100+3)
= (103)^3 = 1000000 + 27 + 900(103)
= (103)^3 = 1000000 + 27 + 92700
= (103)^3 = 1092727
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