Math, asked by saidevsaidev2, 8 months ago

using identity find (3x+y)^2+(3x-y)^2​

Answers

Answered by swapnaritam
0

Answer:

18x^2+2y^2

Step-by-step explanation:

(3x+y)^2+(3x-y)^2

=9x^2+6xy+y^2+9x^2-6xy+y^2

=18x^2+2y^2

Answered by snarinder667
0

Step-by-step explanation:

By using identity,

(a-b)^2=a^2-2ab+b^2

so,

(3x-2y)^2=(3x)^2-2*3x*2y+(2y)^2=

9x^2-12xy+4y^2

HOPE THIS HELP YOU

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