Using identity find 〖(4x+3y)〗^2?
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0
Answer:
16x^2+24xy+9y^2 (using (a+b)^2 identity which is a^2+2ab+b^2)
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1
Answer:
Good Morning !!!!
= (4x+3y)² [(a+b)² = a²+2ab+b²]
a=4x ; b=3y
= (4x)²+2(4x)(3y)+(3y)²
= 16x²+24xy+9y² (or) 16x²+9y²+24xy
Hope ur satisfied.....
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