Math, asked by nashadab1128, 1 year ago

Using Identity find (4x+5) (4x-1)

Answers

Answered by onlinewithaalia
208

Answer:16x²-24x+5.

Step-by-step explanation:

= (4x-5)(4x-1)

FORMULA=(x+a)(x+b)=x² (a+b)x+ab

x=4x;a=-5;b= -1

=(4x)²+(-5+(-1))4x+(-5)(-1).

=16x²-5-1*4x-5*(-1)

=16x²-24x+5.

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Answered by SharadSangha
11

Given:

Equation = (4x+5) (4x-1)

To find:

Value of (4x+5) (4x-1) using appropriate identity=?

Solution:

=> The identity applicable to the equation is:

=> (x+a) (x+b) = x² + (a + b) x × ab

=> where x = variable in the equation

=> a= constant in the equation

=> b= constant in the equation

=> According to the equation (4x+5) (4x-1)

=> The value of variable x = 4x

=> The value of constant a = +5

=> The value of constant b= -1

∴ (4x+5) (4x-1) = (4x)² + (5 + (-1))4x + (5 × (-1)) (∵ plus × minus = minus)

= (4x+5) (4x-1) = 16x² + (4)4x + (-5)

= (4x+5) (4x-1) = 16x² + 16x - 5

Hence, the correct solution for the equation is 16x² + 16x - 5 according to the identity.

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