Question

Using identity, find the following squares?
(i) (2x + 1)2
(ii) (x + 2)​

Answer 1

Answer:

$1) \: \: \: \: \: \: \: \: \: \: \: \: \: \: (2x + 1)^{2} \\ by \: using \: the \: formula \\ \\ (a + b) ^{2} = {a}^{2} + {b}^{2} + 2ab \\ \\ here \: a = 2x \\ b = 1 \: \: \: \: so \\ \\ = ({2x})^{2} + {1}^{2} + 2(2x \times 1) \\ \\ = 4 {x}^{2} + 1 + 4x \\ \\ = 4 {x}^{2} + 1 + 4x \\ \\ \\2) \: \: \: \: \: \: \: \: (x + 2) ^{2} \\ \\ \: by \: using \: the \: formula \\ (a + b) ^{2} = {a}^{2} + {b}^{2} + 2ab \\ \\ here \: a \: = x \\ b = 2 \: \: \: so \\ \\ = {x}^{2} + {2}^{2} + 2(x \times 2) \\ \\ = {x}^{2} + 4 + 2 \times 2x \\ \\ = {x}^{2} + 4 + 4x \\ \\ = {x}^{2} + 4x + 4 \\ \\ \\ hope \: it \: helps$

Answer 2

Answer:

( i ) 16x²+16x+4

( ii ) x²+4x+4

Step-by-step explanation:

( i ) = [(2x+1) 2]²

= (4x+2)²

using identity (a+b)²= a²+2ab+b²

16x²+16x+4 ans

( ii ) = (x+2)²

using identity (a+b)²= a²+2ab+b²

x²+4x+4 ans

thanks