Question

using identity, find the value of 100.1 square​

Answer 1

$Value \:of \: (100.1)^{2}\\= ( 100 + 0.1)^{2}\\= 100^{2} + 2\times 100 \times 0.1 + (0.1)^{2}$

By Algebraic Identity:

$\boxed { \pink { ( a + b) ^{2} = a^{2} + 2ab + b^{2} }}$

$= 10000 + 20 + 0.01\\= 10020.01$

Therefore.,

$\red{ Value \:of \: (100.1)^{2}} \green { = 10020.01 }$

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Answer 2

Answer:

10020.01

Step-by-step explanation:

Given equation =(100.1)²

(100+0.1)²

100²+(0.1)2+2×100×0.1

10000 +0.01+20

10020.01

The value of (100.1)2=10020.01

hope IT HELPs....