Question

using identity find the value of 103 sq please with explaination​

Answer 1

Answer:

103 = 100+3

so

(103)² = (100+3)²

we have ,

(a+b)² = a²+2ab+b²

so (100+3)² = 100²+(2*100*3)+3²

==> 10000+600+9 = 10609 is your answer.

Answer 2

Answer:

Using dentity (a +b)² = a² + 2ab + b²

103² = (100 + 3)² = 100² + 2 × 100 × 3 + 3²

= 10000 + 600 + 9

= 10609