Question

using identity find the value of (999)²​

Answer 1

Step-by-step explanation:

${(999)}^{2}$

$it\: can \: be \: written \: as \: {(1000 - 1)}^{2}$

$since \: it \: is \: in \: the \: form \: of \: {(a - b)}^{2} = {a }^{2} - 2ab + {b}^{2}$

$where \: a \: = 1000 \: \: \: b = 1$

${(1000)}^{2} - 2 \times 1000 \times 1 + {1}^{2}$

$1000000 - 2000 + 1$

$1000001 - 2000$

$998001$

$therefore \: the \: value \: {(999)}^{2} = 998001$