using identity I find (2x + 3y )2
1) 2x*+6xy+3y*
2)4x*+12xy+9y*
3)4x*+6xy+9y*
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Not understood your question
are you telling to factorise it
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Answer:
(2x+3y)(4x
2
−6xy+9y
2
)=(2x+3y)((2x)
2
−2x×3y+(3y)
2
)
(2x+3y)(4x
2
−6xy+9y
2
)=(2x)
3
+(3y)
3
(2x+3y)(4x
2
−6xy+9y
2
)=8x
3
+27y
3
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