Math, asked by jatavsaurabh847, 5 months ago

using identity(I)multiply (2y+5)(2y+5)​

Answers

Answered by jeevi22
2

Answer:

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Step-by-step explanation:

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Here's Your Answer :-✨

(2y - 5)^{2}(2y−5)

2

= (2y)^{2} + 5 {}^{2} - 2(2y)(5)=(2y)

2

+5

2

−2(2y)(5)

{4y}^{2} + 25 - 20y4y

2

+25−20y

Answered by janvhidawra2007
0
Here is the answer
(2y+5) (2y+5)
(2y+5) square
= 2y sq + (2*2y*5) + 5 sq
= 2y sq + 20y + 25 sq
Hope this helps you
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