using identity(I)multiply (2y+5)(2y+5)
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Here's Your Answer :-✨
(2y - 5)^{2}(2y−5)
2
= (2y)^{2} + 5 {}^{2} - 2(2y)(5)=(2y)
2
+5
2
−2(2y)(5)
{4y}^{2} + 25 - 20y4y
2
+25−20y
Answered by
0
Here is the answer
(2y+5) (2y+5)
(2y+5) square
= 2y sq + (2*2y*5) + 5 sq
= 2y sq + 20y + 25 sq
Hope this helps you
(2y+5) (2y+5)
(2y+5) square
= 2y sq + (2*2y*5) + 5 sq
= 2y sq + 20y + 25 sq
Hope this helps you
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