Question

using identity, simplify (2x-7)² + 28x​

Answer 1

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Answer 2

Answer::

(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)

$\huge{\underline{\mathtt{\red{❤}\pink{N}\green{S}\blue{w}\purple{E}\orange{R}}}}$

$\underline{\underline{{\purple{\sf Given}}}}$

$\implies \small \boxed{ \tt \red { {(2x - 7)}^{2} + 28x = 0}}$

$\implies \tt\pink{( {2x - 7) }^{2} + 28x = 0}$

$\: \: \implies \: \: \tt \pink{( {4x }^{2} + 49 - 2 \times 2 \times 7x + 28x) = 0}$

$\implies \tt \pink {( {4x}^{2} + 49 - 28x + 28x) = 0}$

$\implies \tt \pink{ {4x}^{2} + 49 = 0}$

$\implies \tt \pink{ {x}^{2} = - \frac{49}{4} }$

$\implies \tt \pink{x = \sqrt{ \frac{ - 49}{4} } = { \frac{7}{2} }}$

$\implies \small \boxed { \tt \purple {x = \frac{7}{2} }}$