Math, asked by suhani1256, 1 year ago

using identity solve (-20)³+(15)³+(5)³​

Answers

Answered by sneha41046
0

a^3 + b^3 + c^3 = 0

if a+b+c =0

as we know,

=> -20 + 15 + 5

=> 0

since the answer is 0

Answered by dna63
3

\textbf{\underline{\red{Step by step Explanation:-}}}

\textit{\underline{Given,,}}

\mathtt{a=-20,,b=15,,c=5}

\textbf{\underline{Hence,,}}

\mathtt{a+b+c=-20+15+5}

\mathtt{=-20+20}

\mathtt{=-0}

\textit{\underline{Using Identity,,}}

\mathtt{a^{3}+b^{3}+c^{3}=3abc}

\mathtt{=(-20)^{3}+(15)^{3}+(5)^{3}}

\mathtt{=3\times(-20)(15)(5)}

\mathtt{=(-60)(75)}

\mathtt{=-4500}

\textit{\underline{Check,,}}

\mathtt{(-20)^{3}+(15)^{3}+(5)^{3}=-8000+3375+125}

\mathtt{=-8000+3500}

\mathtt{=-4500}

\textit{Hence proved,,}

\textbf{\underline{\pink{Hope it helps you..}}}

Similar questions
Math, 6 months ago