using identity solve the following 27x ^3 -64y^3
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Answered by
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(3x)^3-(4y)^3
=(3x-4y)^3-3.3x 4y (3x+4y)
=(3x-4y)^3-3.3x 4y (3x+4y)
Godlyarora:
which identity you have used
See it's simple what have to do is
27x3 - 64y3 (3x3) - (4y)3
Now use a3-b3 identity
It's (3x)3 not (3x3)
Thanks
by
Answered by
2
27x3-64y3
(3x)3-(4y)3
(3x-4y)(9x2+12xy+16y2)
(3x)3-(4y)3
(3x-4y)(9x2+12xy+16y2)
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