using identity to solve the following 27׳-64y³
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this can be done by using the formula of
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Identity:
x^3-y^3=x^3-y^3-3xy(x-y)
So,
(3x)^3-(4y)^3-3(3x)(4y)(3x-4y)
=(3x-4y)^3
=(3x-4y)(3x-4y)(3x-4y)
Here is your answer buddy..
Plz mark as brainliest!!!!
x^3-y^3=x^3-y^3-3xy(x-y)
So,
(3x)^3-(4y)^3-3(3x)(4y)(3x-4y)
=(3x-4y)^3
=(3x-4y)(3x-4y)(3x-4y)
Here is your answer buddy..
Plz mark as brainliest!!!!
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