Question

using identity to solve the following 27׳-64y³

Answer 1

$27 {x}^{3} - 64 {x}^{3} \\ = {(3x)}^3 - {(4x)}^{3} \\ = (3x - 4y) \: (9 {x}^{2} + 16 {x}^{2} + 12xy)$
this can be done by using the formula of
${x}^{3} - {y}^{3}$

Answer 2

Identity:
x^3-y^3=x^3-y^3-3xy(x-y)
So,
(3x)^3-(4y)^3-3(3x)(4y)(3x-4y)
=(3x-4y)^3
=(3x-4y)(3x-4y)(3x-4y)


Here is your answer buddy..
Plz mark as brainliest!!!!