Question

using identity (x+a)(x+b)=x(x+b)+a(x+b)=x2+xb+xa+ab=x²+x(a+b)+ab find (3a2+4)(3a2+7)​

Answer 1

Answer:

$(x + a)(x + b) = x^{2} + (a+ b)x + ab$

$x = 3a^{2}\\a = 4\\b = 7$

$(3a^{2} + 4)(3a^{2} + 7)\\(3a^{2})^{2} + (4 + 7)3a^{2} + (7)(4) \\9a^{4} + (11)3a^{2} + 28\\9a^{4} + 33a^{2} + 28$

Hope it helps

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