Question

Using identity (x+a) (x+b) = x2 + (a+b)x +ab Simplify 103 X 101​

Answer 1

Answer:

(100+3)(100+1) = 100^2 +(3+1)100 + 3×1

= 10000 + 400 +3

= 10403 is your answer

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Answer 2

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$\huge\underline{\bf\red{Solution:- }}$

103× 104 =(100+3) (100+4)

(x+a) (x+b) =x^2+(a+b) x+ab

Here, x = 100 a= 3,b=4

=(100)^2 +(3+4) (100)+(3) (4)

=(10000+(7) (100) + 12

=10712.