Math, asked by sujansujan9080, 1 year ago

using identity = (x+y)³=x³+y³+3xy(x+y) solve (2a+3b
)³

Answers

Answered by Divyansh50800850

$<html><head><style>h1 { text-shadow: 3px 2px red;}</style></head><body><h1>ANSWER</h1></body></html>$

(2a+3b)³ = (2a)³+(3b)³+3×2a×3b(2a+3b)

$\implies$ 8a³+27b³+18ab(2a+3b)

$\implies$ 8a³+27b³+36a²b+54ab² ....ans.....

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