Math, asked by sujansujan9080, 9 months ago

using identity = (x+y)³=x³+y³+3xy(x+y) solve (2a+3b
)³

Answers

Answered by Divyansh50800850

1

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(2a+3b)³ = (2a)³+(3b)³+3×2a×3b(2a+3b)

$\implies$ 8a³+27b³+18ab(2a+3b)

$\implies$ 8a³+27b³+36a²b+54ab² ....ans.....

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