Question

Using if-else-it statement, write a program
in Java to verify whether the entered number
is odd, even or pime.​

Answer 1

Answer:

import java.util.*;

public class Num

{

public static void main(String args[ ])

{

Scanner in=new Scanner(System.in);

int n,c=0;

System.out.println("Enter the number");

n=in.nextInt();

if(n%2==0)

System.out.println(n + " is a even number");

else

System.out.println(n + " is an odd number");

for(int a=1;a<=n;a++)

{

if(n%a==0)

c++;

}

if(c==2)

System.out.println(n + " is a prime number");

else

System.out.println(n + " is not a prime number");

}

}

Output:

Enter the number

19

19 is a odd number

19 is a prime number

Note:Prime numbers are always odd(except 2) so if you write 19 so it will print it as odd number as well as prime number.