Question

Using integration, find the area of a PQR. the coordinates of vertices being P(1, 6). Q(2,8) and R(3, 4).​

Answer 1

Answer:

39 sq units

Step-by-step explanation:

slope of PQ= 8-6 / 2-1 = 2

equation of PQ= (y-6)=2(x-1)

                        => y=2x+4

slope of QR= 8-4 / 2-3 = -4

equation of QR => y=16-4x

slope of PR = 6-4 / 1-3 = -1

equation of PR=> y= 7-x