Using integration, find the area of a PQR. the coordinates of vertices being P(1, 6). Q(2,8) and R(3, 4).
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Answer:
39 sq units
Step-by-step explanation:
slope of PQ= 8-6 / 2-1 = 2
equation of PQ= (y-6)=2(x-1)
=> y=2x+4
slope of QR= 8-4 / 2-3 = -4
equation of QR => y=16-4x
slope of PR = 6-4 / 1-3 = -1
equation of PR=> y= 7-x
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