Question

Using integration find the area of triangle whose vertices are 2, 3 3, 5 and 4, 4

Answer 1

Answer:

Ar(triangle)= 1/2{(x1(y2-y3)+x2(y3-y1)+x3(y1-y2)}

=1/2 {2(5-4)+3(4-3)+4(3-5)

=1/2{2(1)+3(1)+4(-2)}

= 1/2 {2+3-8}

= 1/2 {-3}

= -3/2

$= | - 3 \div 2|$

=3/2

or

1.5