using kirchhoff rule write the expression for the current I1 I2 and I3
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Applying Kirchhoff’s second rule, we get:
-2 - 4I1 + 3I2 +1= 0
4I1 - 3I2 = - 1 ------------(1)
Also, as per second rule, we get:
-2 - 4I1 - 2I3 + 4 = 0
2I1 + I3 = 1
Writing I3 as sum of I1 and I2, it becomes:
2I1 + (I1 + I2 ) = 1
3I1 + I2 = 1 ------------(2)
Solving 1 and 2, we get:
I1 = 2/13A
I2 = 1 - 3I1 = 7/13A
I3 = I1 + I2 = 9/13A
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