Question

Using Kirchhoff’s current law, write an equation for
the currents I1 , I2 , and I3 at point C.

Answer 1

Answer:

Given by c in 1 sec

v=  

1

2m

​  

=2 m/s

15

π

​  

=12  

∘

 

cos12  

∘

cos

I  

3

​  

=I  

1

​  

+I  

1

​  

......(3)

In Loop 1:

(+4v)−(1v)−(I  

2

​  

.3)−2I  

3

​  

=0

3=3I  

1

​  

+2I  

3

​  

.....(1)

In Loop 2;

(+5v)−(2v)−4I  

1

​  

+3I  

2

​  

=0

3I  

2

​  

=4I  

1

​  

=1v.....(2)

3  

2

​  

−4(I  

3

​  

−I  

2

​  

)=1v

7I  

2

​  

−4I  

3

​  

=2v.....(4)

From eqn (1) and (4),

13I  

2

​  

=7

I  

2

​  

=  

13

7

​  

 and

I  

3

​  

=  

2

3

​  

×  

13

6

​  

=  

13

9

​  

 and

∴I  

1

​  

=I  

3

​  

−I  

2

​  

=  

13

2

​  

A.

Explanation: