Using kirchhoff's rules calculate the current in the arm ac of the given circuit
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The current through the loop I3 is 22/13 A.
Explanation:
Correct statement:
a) use kirchhoff's rules , calculate the current in the arm AC of the given circuit.
Applying kirchoff's junction rule at A node:
I3 = I1 + I2 ......(1)
Applying kirchoff's second rule in loop EFCA:
−30 I1 + 40 − 40 I3 = 0
3I1 + 4I3 = 4 .....(2)
In loop EFDB:
−30I1 + 20 I2 − 80
= 0 − 3I1 + 2I2 = 8 .....(3)
from equation (1) put the value of I3 in equation (2).
3I1 + 4(I1 + I2) = 47I1 + 4I2 = 4 .....(4)
From (3) and (4)
13I1 = −12
I1 = −12 / 13 A
Put I1 in equation (4)
7 × −12 / 13 + 4I2 = 4
4I2 = 4 + 84 / 13
I2 = 34/ 13 A
From equation (1).
I3 = −12 / 13 + 34 / 13
I3=22 / 13 A
Thus the current through the loop I3 is 22/13 A.
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